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Simple and best practice solution for g=(xc)/x equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework@ 䎁 ͑S ` x X Ƃ ĕ C B 䎁 ͂Q N Ԃ̋Ζ A ̊Ԑ X ̋Ɛт̑ A ` m ` j N E V j A グ 80 l j N ōő ̃S t ɂ̂ BSince 154 ` @Copyright (C) 1517 by ROCK ON, All right's reserve
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Cx game-Nc^_ g =dYdb, d `V`db å ZV\ c bmhVa dYaVg^hgr, carå XdXdZ^hr ghcq hVb, YZ ch jicZVbchV HXdbd\cd edad\^hr `fqni, ga^ ch ghc Mdmcd hV`\ \^cccd XV\cq ^gh^cq, `dhdfq=dY ed`VqXVh bc g_mVg, c bdYa^ ef^Zh^ X bdä \^cr, ga^ Wq gad_ V gadb, cVghVXac^ V cVghVXac^b c Wqad Vad\cd hXfZd dgcdXVc^A coffeecup calorimeter initially contains 125 g water, at 242°C Potassium bromide (105g), also at 242°C, is added to the water, and after the KBr dissolves, the final temperature is 211°C Calculate the enthalpy change for dissolving the salt in J/g and kJ/mol Assume that the heat capacity of the solution is 418 J/°C g and that no heat is transferred to the surroundings or to the


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N n A e n B e n q t N q t q t q t Ω −Ω = 1 1 1 1 3 2 1 sin sin 3 sin 2 sin 1 π π π π M M, (7) where Ω =2~sinn 2()N 1 n ω π As we mentioned last time, these modes are essentially standing waves Let's see that this is the case by writing Eq (7) in the form of Eq (6) After we do this, let's also identify the wave~ m Ԃ 1 Ԏ A n ƃp ~ W m ` Y ̎Y n A y ̊X p } ցA v C x g A V X ^ g Ɨ Ԃōs A ̗ ł B } l X N l ̒W o F ̃h D I 瓰 A l b T X l ̋ { a A G قȂǗ j I Ȍ ƁA s s 炵 ˑ s s ł̓V b s O X g Ȃǂ y ߂܂ B݁A n ォ 1 N Ԃɏ Ȃ Ƃ P O O O ނ ̐ p Ă ̂ m Ă ܂ H l ނ́A ̐ K ɂ 邽 ߂ɁA ɂ ̂ ̂ ɂ Ă ܂ @ ̑㏞ Ƃ āA Ȋ N A n ̐ Ԍn ɏd ȂЂ ݂ n ߂Ă ܂ @ ̂܂܂䂭 21 I ɂ́A1 Ԃ 1 A N Ԃɒ ƁA Ȃ 9000 ߂ ł Ă䂭 ƂɂȂ ܂ @ ̐ Ȏ Ԃ H ~ ߂ ɂ́A ł ̐l X ̗ Ƌ ͂ K v ł @ C Ƃ R g ߂ɑΛ Ă 鎄 _ C o A Ɗ ɊS A l ЂƂ肪 悵 Ċ ی


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